Using Punnett Squares to    Hour   1 2 3 4 5          Name                                             
Predict the Outcomes of Crosses

     The possible gene combinations in the offspring that result from a genetic cross can be determined by drawing a diagram known as a Punnett square.  A Punnett square shows the genes (represented by letters) in the parents’ gametes along the top and left-hand side of a square and the possible gene combinations in the offspring, within the square.
     A completed Punnett square gives the probable outcome of a given cross.  However, actual results may vary from the probable results, especially if only a few organisms are considered.

ONE-FACTOR CROSSES
     Crosses that involve one trait, such as seed coat color, are called one-factor crosses.  For the one-factor crosses in this activity, we will use some of the traits Mendel observed in pea plants.  The expressions of the dominant and recessive alleles for the genes controlling these traits are described in the following chart.  The cart also assigns letters to represent the different alleles.
 
 

                    Trait             Dominant Allele           Recessive Allele
             Pod Shape            Smooth  (NN, Nn)           Constricted (nn)
             Pod Color            Green (GG, Gg)           Yellow (gg)
            Flower Position            Axial (AA, Aa)           Terminal (aa)
            Plant height            Tall (TT, Tt)           Short (tt)

     In the example that follows, we will predict the results of a cross between a plant that is heterozygous (Gg) for green pods and a plant that has yellow pods (recessive = gg).

Sample Problem
     A plant that is heterozygous for green pods it crossed with a plant that has yellow pods.  What are the probable genotypic and phenotypic ratios in the offspring resulting from this cross?

Step 1    Choose a letter to represent the alleles in the cross.
     G for the dominant green allele and g for the recessive yellow allele.

Step 2    Write the genotypes of the parents.
     Since the plant with green pods is heterozygous for the trait, its genotype must be Gg.  The problem does not state whether the plant with yellow pods is homozygous or heterozygous.  But we know that yellow pods are a recessive character, and that recessive characters are expressed only in a homozygous recessive individual.  Thus the genotype of this plant must be gg.  The cross, therefore, it Gg X gg.
 
Step 3     Determine the possible gametes (reproductive cells) that the parents can produce.
     The two alleles of any gene are segregated during the formation of gametes.  Thus the green-pod parent (Gg) will produce two kinds of gametes— G and g.  The yellow-pod parent (gg) will produce g gametes.

Step 4     Enter the possible gametes at the top and side of the Punnett square.

G  g
 g    
 g    

Step 5     Complete the Punnet square by writing in the alleles in the appropriate boxes.
     This step represents the precess of fertilization, in which a male gamete from one parent combines with the female gamete from the other parent.  To predict all possible offspring genotypes, each type of possible gamete from one parent is combined with each possible type of gamete from the other parent.

  The completed Punnet square for this problem would look like this:
 

G  g
 g Gg gg
 g Gg gg

   As you can see, ½ of the offspring are genotype Gg and ½ are gg.

Step 6    Determine the phenotypes of the offspring.
     Since green (G) is dominant over yellow (g), plants that have G in their genotypes have green pods.   Only plants with genotypes gg have yellow pods.   In this example, ½ of the offspring have green pods and ½ have yellow pods.

Step 7    Using the results of steps 5 and 6, answer the problem.
 In this example, the genotypic ratio is 2 Gg : 2 gg, or 1:1.   The phenotypic ratio is 2 green:2 yellow or 1:1.

Practice Problems
     For each of the following problems, draw a Punnett square in the space provided and fill in the information on the indicated lines.  Refer to the table on page 183 of your textbook for a description of pea traits.

 1.  Nn x NN                                  2.  Aa x aa                                     3.  Tt x Tt
 

 
 
 

1.  Genotypic ratio:                         2.  Genotypic ratio:                          3. Genotypic ratio:
     Phenotypic ratio:                             Phenotypic ratio:                            Phenotypic ratio:
 

4.  Cross two plants that are heterozygous for green pods.

          Genotypic ratio

          Phenotypic ratio
 
 
 
 
 

5.  Cross a plant that is heterozygous for axial flowers with a plant that has terminal flowers.

          Genotypic ratio

          Phenotypic ratio

 

6.  Cross a homozygous tall plant with a short plant.

          Genotypic ratio

          Phenotypic ratio
 
 

7.  Cross a plant that is heterozygous for smooth pods with a plant that has constricted pods.

          Genotypic ratio

          Phenotypic ratio
 
 

8.  When a tall plant is crossed with a short plant, some of the offspring are short.  What are the genotypes of the parents and the offspring?  What is the phenotypic ratio in the offspring?

          Parent Genotype:
 
          Offspring genotypes:

          Phenotypic ratio:

9.  Three-fourths (3/4) of the plants produced by a cross between two unknown pea plants have axial flowers and 1/4 have terminal flowers.  What are the genotypes of the parent plants?

          Parent genotypes:
 
 
 
 

10.  What cross would result in ½ of the offspring having green pods and ½ of the offspring having yellow pods?

           Cross:
 
 
 
 
 
 

TWO FACTOR CROSSES

 Crosses that involve two traits, such as pod color and pod shape, are called two-factor crosses.  Predicting the outcome of two-factor crosses requires basically the same procedure as that for crosses involving one trait.  Keep in mind that in two-factor crosses the genes controlling the two different traits are located on nonhomologous chromosomes.  During meiosis, nonhomologous chromosomes assort independently.  This means that each of the chromosomes of any pair of homologous chromosomes has an equal probability of ending up in a gamete with either chromosome from any other pair of homologous chromosomes.  The genes that are located on nonhomologous chromosomes also assort independently, as you can see in the following diagram.
 
 
 
 
 
 
 
 
 

 Because of independent assortment, a plant that is heterozygous for two traits (genotype AaBb) will produce equal numbers of four types of gametes - AB, Ab, aB, and ab.
 In the example that follows, we will predict the results of a cross between two plants that are heterozygous for both pod color and pod shape.

Sample Problem
 What are the genotypic and phenotypic ratios in the offspring resulting from a cross between two pea plants that are heterozygous for pod color and pod shape?  What is the phenotype of the parents in this cross?

    Step 1     Choose letters to represent the genes in the cross.
 Let’s use the letters we used in the one-factor crosses - G for green and g for yellow, N for smooth, and n for constricted.

     Step 2     Write the genotypes of the parents.
 Since the parents are heterozygous for both traits, their genotype must be GgNn.  The cross can be
 written as GgNn X GgNn.

     Step 3     Determine the possible gametes that the parents can produce.
 Each parent produces four types of gametes - GN, Gn, gN, and gn.

     Step 4     Enter the possible gametes at the top and side of the Punnett square.
 

         GN       Gn       gN       gn
      GN        
      Gn        
      gN        
      gn        

     Step 5     Complete the Punnett square by writing the alleles from the gametes in the appropriate boxes.
 The alleles from the gamete above the box and the alleles from the gamete to the side of the box are combined inside each of the boxes.  Write the capital letter first for each pair of alleles.  The letters inside each box represent the probable genotypes of the offspring resulting from the cross.
 

         GN       Gn       gN       gn
      GN    GGNN    GGNn      GgNn     GgNn
      Gn    GGNn    GGnn     GgNn     Ggnn
      gN    GgNN    GgNn     ggNN     ggNn
      gn    GgNn    Ggnn     ggNn     ggnn

     Step 6     Determine the phenotypes of the offspring.
 In this example, 9/16 have green smooth pods, 3/16 have yellow smooth pods, 3/16 have green constricted pods, and 1/16 have yellow constricted pods.

     Step 7     Using the results of steps 5 and 6, answer the problem.
 Note that in this example, as in many of the genetics problems you will encounter, you are asked for more than just the ratios resulting from the cross.  This is one reason why it is important to read genetics problems carefully.  In this example, the genotypic ratio is 1/16: 2/16: 1/16: 2/16: 4/16: 2/16: 1/16: 2/16: 1/16 = 1 : 2 : 1 : 2 : 4 : 2 : 1 : 2 : 1.   The phenotypic ratio is 9/16 : 3/16 : 3/16 : 1/16 = 9 : 3 : 3 : 1.  The phenotype fo the parent is green smooth pods.

Practice Problems
 In mice, the ability to run normally is a dominant trait.  Mice with this trait are called running mice (R_).  The recessive trait causes mice to run in circles only.  Mice with this trait are called waltzing mice (rr).  Hair color is also inherited in mice.  Black hair (B_) is dominant over brown hair (bb).  For each of the following problems, draw a Punnett square in the space provided and fill in the information on the indicated lines.

 1.  Cross a heterozygous running, heterozygous black mouse with a homozygous running, homozygous black mouse.

         Parental genotypes:

         Phenotypic ratio:
 
 
 
 
 

 2.  Cross a homozygous running, homozygous black mouse with a heterozygous running, brown mouse.

         Parental genotypes:

         Phenotypic ratio: 

 
 3.  Cross a waltzing brown mouse with a waltzing brown mouse.

         Parental genotypes:

         Phenotypic ratio:
 
 

 4.  Cross a homozygous running, heterozygous black mouse with a waltzing brown mouse.

         Parental genotypes:

         Phenotypic ratio:  
 
 
 

 5. Cross a heterozygous running, brown mouse with a heterozygous running, homozygous black mouse.

         Parental genotypes:

         Phenotypic ratio:    
 
 
 

 6. Cross two heterozygous running, heterozygous black mice.

         Parental genotypes:

         Phenotypic ratio:   
 
         Genotypic ratio:   
 
 
 
 
 
 
 
 
 
 

 7.  Cross a waltzing, homozygous black mouse with a heterozygous running, brown mouse.

         Parental genotypes:

         Phenotypic ratio: